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x^2+2x+.75=0
We add all the numbers together, and all the variables
x^2+2x+0.75=0
a = 1; b = 2; c = +0.75;
Δ = b2-4ac
Δ = 22-4·1·0.75
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-1}{2*1}=\frac{-3}{2} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+1}{2*1}=\frac{-1}{2} =-1/2 $
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